Python - creating 2 dice to roll fairly and add them together? -

so had make code roll die , counted how many 4's got. of people on here got work. have created die , roll them , add products together. instructions i've been given.

"then write function simulates rolling 2 fair dice. easy way call function wrote, twice, , add numbers get. should return number between 2 , 12."

i've added rolling dice second time how add sums of 2 rolls question? , code.

from random import randrange def roll():     rolled = randrange(1,7)     if rolled == 1:         return "1"     if rolled == 2:         return "2"     if rolled == 3:         return "3"     if rolled == 4:         return "4"     if rolled == 5:         return "5"     if rolled == 6:         return "6"  def rollmanycounttwo(n):     twocount = 0     in range (n):         if roll() == "2":             twocount += 1         if roll() == "2":             twocount +=1     print ("in", n,"rolls of pair of dice, there were",twocount,"twos.")  rollmanycounttwo(6000) 

you shouldn't have deal strings @ all, done entirely using int values

from random import randint  def roll():     return randint(1,6)  def roll_twice():     total = 0     turn in range(2):         total += roll()     return total 

for example

>>> roll_twice() 10 >>> roll_twice() 7 >>> roll_twice() 8 

and function supposed count number of 2s rolled, again can integer comparison

def rollmanycounttwo(n):     twos = 0     turn in range(n):         if roll() == 2:             twos += 1     print('in {} rolls of pair of dice there {} twos'.format(n, twos))     return twos  >>> rollmanycounttwo(600) in 600 rolls of pair of dice there 85 twos 85