c++ - #define as unsigned char -

i know how can tell compiler #define unsigned char. if #define 1 byte this:

   #define aaceess_pss 0x80     #define access_pss  ((unsigned char)0x80) 

but if #define has more byte should do?? example:

 #define access_pss {0x32,0xfd,0x6e,0x2d} 

i need cast assign #define unsigned char

int main(){ unsigned char responsedata[100]; (int = 0; <4;i++0){                  if (responsedata[i+5]==access_pss){ //how this???                             cout<<5<<endl;                                           } 

responsedata programm value , byte 5 8 equal access_pss.

responsedata[i+5]==access_pss

you can't compare 4 unsigned chars single equality operator in c.

you can convert uint32_t, may break due unaligned access or different endianness, i.e.:

#define access_pss    0x32fd6e2d ... if(*((uint32_t*) (responsedata + + 5)) == access_pss) { /*...*/ } 

the clean way memcmp, or similiar function:

const unsigned char access_pss[4] = {0x32,0xfd,0x6e,0x2d}; ... if(memcmp(responsedata + + 5, access_pss, 4) == 0) { /*...*/ }