java - Number Format Exception - converting with parseInt -

i working @ converting string number binary. eclipse throws numberformatexception. can ask you, @ code? have no idea wrong..

public float liczbaf(string lancuch){     float array [] = new float [31];     float liczba;     double mantysa;     int znak;     long cecha;     char element[] = new char[22];     string temp="";       if (lancuch.charat(0)=='1')         znak=-1;     else         znak=1;       for(int i=1;i<8;i++)         {         element[i-1] = lancuch.charat(i);         }      temp=string.valueof(element);     system.out.println(temp);     cecha=integer.parseint(temp,10);     cecha=cecha-127;     system.out.println(cecha);      for(int i=31;i>9;i--)     {     element[31-i] = lancuch.charat(i);     }     temp=string.valueof(element);     mantysa=(((integer.parseint(temp,10))/(pow(2,22)))+1);     liczba=(float)(mantysa*pow(2,cecha));     return liczba; } 

it throws:

exception in thread "main" java.lang.numberformatexception: input string: "1001101 @ java.lang.numberformatexception.forinputstring(unknown source) @ java.lang.integer.parseint(unknown source) @ konwersja.liczbaf(konwersja.java:30) @ main.main(main.java:10) 

i grateful help. thank you

your element array 22 long:

 char element[] = new char[22]; 

but fill in first 7 elements:

 for(int i=1;i<8;i++)     {     element[i-1] = lancuch.charat(i);     } 

so there null characters @ end of string, make unparseable integer. works better:

temp=string.valueof(element,0,7); 

i recommend using stringbuilder add characters string, not char array.