php - Extract ZIP's contents on screen but avoid extra information except of the file names -

i looking command print contents of archive (including sub-folders , it's files) without extracting actual archive on disk, on screen.

i achieve using other questions , answers site, , here command:

unzip -l test.zip | awk '/-----/ {p = ++p % 2; next} p {print $nf}' 

the output:

0 04-11-2009 13:43 jodconverter-webapp-2.2.2/ 1815 04-11-2009 13:43 jodconverter-webapp-2.2.2/readme.txt 0 04-11-2009 13:43 jodconverter-webapp-2.2.2/src/ 5349 04-11-2009 13:42 jodconverter-webapp-2.2.2/src/jodconverter-webapp-2.2.2-sources.jar 26436 04-11-2009 13:43 jodconverter-webapp-2.2.2/license.txt 3819 04-11-2009 13:43 jodconverter-webapp-2.2.2/changelog.txt 3314202 04-11-2009 13:42 jodconverter-webapp-2.2.2/jodconverter-webapp-2.2.2.war 

as can see output 1 line, , includes information don't need.

i want output of kind:

jodconverter-webapp-2.2.2/ jodconverter-webapp-2.2.2/readme.txt jodconverter-webapp-2.2.2/src/ jodconverter-webapp-2.2.2/src/jodconverter-webapp-2.2.2-sources.jar . . . 

so not want output file names (and full path) , avoid other information time permissions , on, want use break-line distinguish different files.

keep in mind command run on php file contents of file, don't know if can use <br> break lines.

is possible single command?

well, can't think command return output need, may else can know more.

what in case split line array , play until want.

you have find pattern work cases. brief on command's output came following decisions:

1. you splitting line using separator space (i.e explode() )
2. the pattern can see there exist time of form xx:xx before actual file/directory ! can check if current line valid 24-based time using regular expression means if case , in $i position of array $i+1 looking for, , therefore can copy new array.
3. repeat

i think bit pain, @ least solution.