android - Get the current time when the user comes out of an item in a listview -


i have horizontal listview contains albums. want time when user opens , closes album. able time when album opened , don't know how can time when user comes listview.

here code,

listview1.setonitemclicklistener(new onitemclicklistener() {              @override             public void onitemclick(adapterview<?> parent, view v,                     int position, long arg3) {                 try {                      jsonobject = new arraylist<jsonobjectclass>();                     jsonobjectclass jsondata = new jsonobjectclass();                     string datetime = (string)getdatetime();                      gps = new gpstracker(mainphotoalbumactivity.this);                      // check if gps enabled                     if(gps.cangetlocation()){                          double latitude = gps.getlatitude();                         double longitude = gps.getlongitude();                          jsondata.lattitue = latitude;                         jsondata.longitude = longitude;                         jsondata.album_opened = datetime;                         jsondata.license_key = new homeactivity().lickey;                          toast.maketext(getapplicationcontext(), "your location - \nlat: " + latitude + "\nlong: " + longitude, toast.length_long).show();                     }else{                         // can't location                         // gps or network not enabled                         // ask user enable gps/network in settings                         gps.showsettingsalert();                     }                     albumnameforcontent = thumbnails1.get(position).albumname                             .substring(thumbnails1.get(position).albumname                                     .lastindexof("/") + 1);                       jsondata.album_name = albumnameforcontent;  //code display each image in album..  }

please let me know how can done.. :)

i found way time wen user closes album. implemented onbackpressed() in activity, when ever user clicks button (meaning s exiting album) take current time.


Comments

Post a Comment

Popular posts from this blog

How to connect android app to App engine -

i'm trying connect app in android server i've opened on appengine. my server's name : dddd-daniel-2345 , website server : http://dddd-daniel-2345.appspot.com/ this how connect android app server in app engine: app.yaml: application: dddd-daniel-2345 version: 1 runtime: python27 api_version: 1 threadsafe: yes handlers: - url: .* script: main.app libraries: - name: webapp2 version: "2.5.2" main.py: #!/usr/bin/env python # # copyright 2007 google inc. google.appengine.api import users import webapp2 class userhandler(webapp2.requesthandler): def get(self): user = users.get_current_user() if user: greeting = ('%s,%s,%s' % (user.email(),user.user_id(),user.nickname())) else: greeting = ('not logged in') self.response.out.write(greeting) app = webapp2.wsgiapplication([('/', userhandler),], debug=true) my applications code : add manifast main....
Read more

gcc - MinGW's ld cannot perform PE operations on non PE output file -

i know there other similar questions out there, stackoverflow or not. i've researched lot this, , still didn't find single solution. i'm doing operative system side project. i've been doing in assembly, wanna join c code. test, made assembly code file (called test.asm): [bits 32] global _a section .text _a: jmp $ then made c file (called main.c): extern void a(void); int main(void) { a(); } to link, used file (called make.bat): "c:\mingw\bin\gcc.exe" -ffreestanding -c -o c.o main.c nasm -f coff -o asm.o test.asm "c:\mingw\bin\ld.exe" -ttext 0x100000 --oformat binary -o out.bin c.o asm.o pause i've been researching ages, , i'm still struggling find answer. hope won't flagged duplicate. acknowledge existence of similar questions, have different answers, , none work me. question: what doing wrong? old mingw versions had problem "ld" not able create non-pe files @ all. maybe current versions...
Read more

php - display validation error message next to the textbox in codeigniter -

Image
i'm newbie codeigniter.i want display error message next text box.my view file create.php contains following code. <?php echo validation_errors(); //validation echo form_open('news/create'); //create form ?> <div class="boxes"> <div class="common"> <div class="lables"> <label for="name">name</label> </div> <div class="text_boxes"> <input type="text" name="uname" /><div id="infomessage"><?php echo $message;?></br> </div> </div>` and below controller model: public function create() { $this->load->helper('form'); $this->load->library('form_validation'); $data['title'] = 'insert items'; $this->form_validation->set_rules('uname','required|min_length[6]|m...
Read more