Operator precedence in C for the statement z=++x||++y&&++z -


i studying operator precedence , not able understand how value of x became 2 , of y , z 1

x=y=z=1;  z=++x||++y&&++z;

this evaluates to

x=2 y=1 z=1

++ has higher priority ||, whole rhs of assignment boils down increment of x , evaluation truth value (1).

z = ++x         ||  ++y&&++z;     truthy (1)     never executed

this because ++x evaluates true , second branch not executed. ++x 2 which, in boolean context, evaluates true or 1. z takes value of 1, giving observed final state.


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