javascript - How to retrieve data achieved through PHP and JSON properly (with parse) -


everybody!

i'm thinking have problem json.parse

i submitted form ajax php page.

index.php - full code          jquery('#inserir_certificado_usuario').submit(function(){              var dados = jquery( ).serialize();             jquery.ajax({             type: "post",             url: "../classes/processa_evento.php",             data: dados,             success: function(data)             {              var data = data;              var arr = json.parse(data);                 var i;                 var out = "";                 for(i = 0; < arr.certificado.length; i++) {                 out += "trabalho: " +                      arr.certificado[i].id_trabalho + " - " + arr.certificado[i].titulo_trabalho +                     "<br />usuário: " +                     arr.certificado[i].id_usuario + " - " + arr.certificado[i].nome_autor +                     "<br />autenticador nº: " +                     arr.certificado[i].autenticador +                     "<br /><a href='../certificados/ver_certificado.php?caso=0&autenticador="+arr.certificado[i].autenticador+"' target='certificado'>ver certificado</a>";                                                 }                 out += "";                 document.getelementbyid("divcarregadestinatarios").innerhtml = out;             },             error: function()             {            //do nothing               }             });             return false;             });      <div id='divcarregadestinatarios'></div>

the data received this.

processa_evento.php      $autenticador = $_post[autenticador];     $id_certificado_base = $_post[id_certificado_base];     $id_evento_certificado = $_post[id_evento_certificado];     $id_trabalho = $_post[id_trabalho];     $titulo_trabalho = $_post[titulo_trabalho];     $id_usuario = $_post[id_usuario];     $nome_autor = $_post[nome_autor];     $timestamp_certificado = $_post[timestamp_certificado];     $token_trabalho = $_post[token_trabalho];  //create code json     $json_resposta['certificado'] = array('id_trabalho'=>"$id_trabalho", 'titulo_trabalho'=>"$titulo_trabalho", 'id_usuario'=>"$id_usuario", 'nome_autor'=>"$nome_autor", 'autenticador'=>"$autenticador");      $json_resposta = json_encode($json_resposta, json_hex_tag | json_hex_apos | json_hex_quot | json_hex_amp | json_unescaped_unicode);      //replace \\n cause errors in javascript     $json_resposta = str_replace("\\n", " ", $json_resposta);      echo "$json_resposta";     //echo       //{"certificado":[{"id_trabalho":"13","titulo_trabalho":"o problema da degradaÇÃo ambiental e gestÃo no municÍpio de guaramiranga - cearÁ: um olhar sobre lei 110\/2005","id_usuario":"8","nome_autor":"ariana  rodrigues bezerra ","autenticador":"ohic.srzl.nzat.w2pq.a5x0.kykd"}]}

so, returning index.php i'm retrieving data php page (processa_evento.php) through ajax using "success method":

index.php     ...     success: function(data)             {              var data = data;     ...

after tha retrieved data, create html elements javascript , data using code:

index.php     ...     var arr = json.parse(data);                 var i;                 var out = "";                 for(i = 0; < arr.certificado.length; i++) {                 out += "trabalho: " +                      arr.certificado[i].id_trabalho + " - " + arr.certificado[i].titulo_trabalho +                     "<br />usuário: " +                     arr.certificado[i].id_usuario + " - " + arr.certificado[i].nome_autor +                     "<br />autenticador nº: " +                     arr.certificado[i].autenticador +                     "<br /><a href='../certificados/ver_certificado.php?caso=0&autenticador="+arr.certificado[i].autenticador+"' target='certificado'>ver certificado</a>";                                                 }                 out += "";                 document.getelementbyid("divcarregadestinatarios").innerhtml = out;

but how i'm getting error (mozilla firebug) @ index.php:

syntaxerror: json.parse: unexpected character @ line 1 column 1 of json data console.log(json.parse(data))

what happening? i'm new @ this. me, please? best regards, folks!


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