c++ - explicit type casting float(intvar) results in int -


i tried following code :

#include <iostream> #include<conio.h> using namespace std; int main() {     int intvar = 25;     float floatvar = 35.87;     cout << "intvar= " << intvar;     cout << "\n floatvar =" << floatvar;     cout << "\n float(intvar)=" << float(intvar);     cout << "\n int(floatvar)=" << int(floatvar);     _getch();     return 0; }

the result float(intvar) coming 25.
can please explain why still being shown integer , not 25.000000?

the value not integer, it's std::cout try give compact representation here. use setfixed , setprecision (from #include <iomanip>) force specific output precision on floats. add before first cout line:

cout << fixed << setprecision(6);

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