Python - rolling a dice fairly and counting how many 4's I get -


so had make code roll die , counted how many 4's got. of on here got work. have created die , roll them , add products together. instructions i've been given.

"then write function simulates rolling 2 fair dice. easy way call function wrote, twice, , add numbers get. should return number between 2 , 12. should calculate both numbers in 1 run – counting 2 distinct things."

and code freshly fixed.

from random import randrange def roll():     rolled = randrange(1,7)     if rolled == 1:         return "1"     if rolled == 2:         return "2"     if rolled == 3:         return "3"     if rolled == 4:         return "4"     if rolled == 5:         return "5"     if rolled == 6:         return "6"   def rollmanycounttwo(n):     twocount = 0     in range (n):         if roll() == "2":             twocount += 1     print ("in", n,"rolls of pair of dice, there were",twocount,"twos.")  rollmanycounttwo(6000)

you shouldn't calling randrange() inside roll() in every if condition, instead should call once , save in variable , check.

the code -

from random import randrange def roll():     rolled = randrange(1,7)     if rolled == 1:         return "1"     if rolled == 2:         return "2"     if rolled == 3:         return "3"     if rolled == 4:         return "4"     if rolled == 5:         return "5"     if rolled == 6:         return "6"   def rollmanycountfour(n):     fourcount = 0     in range (n):         if roll() == "6":             fourcount += 1     print ("in", n,"rolls of due, there were",fourcount,"fours.")  rollmanycountfour(6000)

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