javascript - I want to match data from my database to googlelocation dropdown -


this website underconstruction please go upper link , click on signup drive (blue cruve button) there tab open type london (not drop down) type london , hit enter page redirect

dev.appcotech.com/pwrdup/static/become-postie-vehicle.php

page (this mean post keyword matched 100% database) come previous page , again type london time dropdown menu find london, united kingdom,and hit enter. same city database have keyword london.so page redirect

dev.appcotech.com/pwrdup/static/city-unavailables.php

this mean result not matched 100%

i want match city london, united kingdom database keyword london. have letters london in database here code.

require_once "connection/connection.php"; if($_post) {     $a  = $_post['address'] ;    $sql = "select * tbl_city city_name '%$a%'";     $res  = mysql_query($sql);       $result = mysql_fetch_array($res);      if($result >=1){        header("location:become-postie-vehicle.php");        die();       }else{        header("location:city-unavailables.php");        die();    }

where $a = $_post['address'] ; input field name (where use search) please let me know how can match city database?my database given below

create table if not exists `tbl_city` ( `id` int(100) not null,  `city_name` varchar(100) not null  ) engine=innodb auto_increment=2 default charset=latin1;     insert `tbl_city` (`id`, `city_name`) values   (1, 'london');

now please me find out solution. remember have used regexp match() ... against in $sql already.it challenging ever. anyone have solution???

i have got answer daniweb.com

if you're going have same format of city comma followed something, write query substring_index split on comma. if isn't going way, of course wouldn't able that.

select * tbl_city city_name substring_index('london, united kingdom', ',', 1);

this splits string on first comma, , uses value of 'london' in search.

or

you split string in php prior running query.


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