python - a simple command -- "np.save", maybe i misunderstood -

examples

from tempfile import temporaryfile  outfile = temporaryfile()  x = np.arange(10)  np.save(outfile, x)

after command (highlighted), why not find output file called "outfile" in current directory? sorry may sound stupid

outfile.seek(0) # needed here simulate closing & reopening file  np.load(outfile)  array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])

it because using - temporaryfile , temporary file not stored outfile in directory.

if want save outfile , can give name , save file.

np.save('outfile',x)

when saving load, need use , again filename string -

np.load('outfile')

Macro